5,6t^2-13.3=0

Solution for 5,6t^2-13.3=0 equation:

5.6t^2-13.3=0

a = 5.6; b = 0; c = -13.3;
Δ = b2-4ac
Δ = 02-4·5.6·(-13.3)
Δ = 297.92
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{297.92}}{2*5.6}=\frac{0-\sqrt{297.92}}{11.2}
=-\frac{\sqrt{}}{11.2}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{297.92}}{2*5.6}=\frac{0+\sqrt{297.92}}{11.2}
=\frac{\sqrt{}}{11.2}
$